tools/common/piglatin.c

/*
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 * The contents of this file are subject to the terms of the
 * Common Development and Distribution License (the "License").
 * You may not use this file except in compliance with the License.
 *
 * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE
 * or http://www.opensolaris.org/os/licensing.
 * See the License for the specific language governing permissions
 * and limitations under the License.
 *
 * When distributing Covered Code, include this CDDL HEADER in each
 * file and include the License file at usr/src/OPENSOLARIS.LICENSE.
 * If applicable, add the following below this CDDL HEADER, with the
 * fields enclosed by brackets "[]" replaced with your own identifying
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/*
 *  Copyright 2007 Sun Microsystems, Inc.
 *  All rights reserved.
 *  Use is subject to license terms.
 *
 * Very crude pig latin converter.
 * Piglatin is an encoded form of English that is often used by  children
 * as a game. A piglatin word is formed from an English word by:
 *
 *  .   If the word begins with a consonant, move the consonant to the end of
 *  the word and append the letters "ay". Example: "door" becomes "oorday".
 *
 *  .   If the word begins with a vowel, merely append "way" to the word.
 *  Example: "ate" becomes "ateway
 */
#pragma ident   "%Z%%M% %I% %E% SMI"

#include <stdio.h>
#include <strings.h>
#include <ctype.h>

int
main()
{
    char    buffer[32767], * cb, * sb;
    int ic, ignore = 0, word = 0;

    sb = cb = &buffer[0];
    *sb = '\0';

    while ((ic = getc(stdin)) != EOF) {
        char c = (char)ic;

        /*
         * Ignore all possible formatting statements.
         */
        if (c == '%')
            ignore = 1;

        /*
         * Isolate the word that will be converted.
         */
        if (isspace(ic) || (ispunct(ic) && ((ignore == 0) ||
            ((c != '%') && (c != '.') && (c != '#') && (c != '-'))))) {
            char s = buffer[0];

            /*
             * If we haven't collected any words yet simply
             * printf the last character.
             */
            if (word == 0) {
                (void) putc(ic, stdout);
                continue;
            }

            /*
             * Leave format strings alone - contain "%".
             * Leave single characters alone, typically
             * these result from "\n", "\t" etc.
             */
            if ((ignore == 0) && ((cb - buffer) > 1)) {
                if ((s == 'a') || (s == 'A') ||
                    (s == 'e') || (s == 'E') ||
                    (s == 'i') || (s == 'I') ||
                    (s == 'o') || (s == 'O') ||
                    (s == 'u') || (s == 'U')) {
                    /*
                     * Append "way" to the word.
                     */
                    (void) strcpy(cb, "way");
                } else {
                    /*
                     * Move first letter to the end
                     * of the word and add "ay".
                     */
                    sb++;
                    *cb = s;
                    (void) strcpy(++cb, "ay");
                }
            } else
                *cb = '\0';

            /*
             * Output the collected buffer, the last character
             * read and reinitialize pointers for next round.
             */
            (void) printf("%s", sb);
            (void) putc(ic, stdout);

            sb = cb = &buffer[0];
            word = ignore = 0;

            continue;
        }

        /*
         * Store this character into the word buffer.
         */
        *cb++ = c;
        *cb = '\0';
        word = 1;
    }

    return (0);
}