/**
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS HEADER.
*
* Copyright (c) 2005 Sun Microsystems Inc. All Rights Reserved
*
* The contents of this file are subject to the terms
* of the Common Development and Distribution License
* (the License). You may not use this file except in
* compliance with the License.
*
* You can obtain a copy of the License at
* https://opensso.dev.java.net/public/CDDLv1.0.html or
* opensso/legal/CDDLv1.0.txt
* See the License for the specific language governing
* permission and limitations under the License.
*
* When distributing Covered Code, include this CDDL
* Header Notice in each file and include the License file
* at opensso/legal/CDDLv1.0.txt.
* If applicable, add the following below the CDDL Header,
* with the fields enclosed by brackets [] replaced by
* your own identifying information:
* "Portions Copyrighted [year] [name of copyright owner]"
*
* $Id: ByteArrayLexOrder.java,v 1.2 2008/06/25 05:52:43 qcheng Exp $
*
*/
package com.iplanet.security.util;
import java.util.Comparator;
/**
* Compare two byte arrays in lexicographical order.
*/
public class ByteArrayLexOrder implements Comparator {
/**
* Perform lexicographical comparison of two byte arrays, regarding each
* byte as unsigned. That is, compare array entries in order until they
* differ--the array with the smaller entry is "smaller". If array entries
* are equal till one array ends, then the longer array is "bigger".
*
* @param obj1
* first byte array to compare.
* @param obj2
* second byte array to compare.
* @return negative number if obj1 < obj2, 0 if obj1 == obj2, positive
* number if obj1 > obj2.
*
* @exception <code>ClassCastException</code> if either argument is not a
* byte array.
*/
public final int compare(Object obj1, Object obj2) {
byte[] bytes1 = (byte[]) obj1;
byte[] bytes2 = (byte[]) obj2;
int diff;
for (int i = 0; i < bytes1.length && i < bytes2.length; i++) {
diff = (bytes1[i] & 0xFF) - (bytes2[i] & 0xFF);
if (diff != 0) {
return diff;
}
}
// if array entries are equal till the first ends, then the
// longer is "bigger"
return bytes1.length - bytes2.length;
}
}