Code39Ext.py revision 040e298be5b23e77e33309d65449072183c82d5c
'''
Copyright (C) 2007 Martin Owens
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 2 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; if not, write to the Free Software
Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
'''
import Code39
encode = list('ABCDEFGHIJKLMNOPQRSTUVWXYZ')
map = {}
i = 0
for char in encode:
map[char] = i
i = i + 1
# Extended encoding maps for full ASCII Code93
def getMap(array):
result = {}
y = 0
for x in array:
result[chr(x)] = encode[y]
y = y + 1
return result;
# MapA is eclectic, but B, C, D are all ASCII ranges
mapA = getMap([27,28,29,30,31,59,60,61,62,63,91,92,93,94,95,123,124,125,126,127,0,64,96,127,127,127]) # %
mapB = getMap(range(1, 26)) # $
mapC = getMap(range(33, 58)) # /
mapD = getMap(range(97, 122)) # +
class Object(Code39.Object):
def encode(self, text):
# We are only going to extend the Code39 barcodes
result = ''
for char in text:
if mapA.has_key(char):
char = '%' + mapA[char]
elif mapB.has_key(char):
char = '$' + mapB[char]
elif mapC.has_key(char):
char = '/' + mapC[char]
elif mapD.has_key(char):
char = '+' + mapD[char]
result = result + char
return Code39.Object.encode(self, result);