common/C/exp10.c

	exp10.c revision 25c28e83beb90e7c80452a7c818c5e6f73a07dc8
/*
 * CDDL HEADER START
 *
 * The contents of this file are subject to the terms of the
 * Common Development and Distribution License (the "License").
 * You may not use this file except in compliance with the License.
 *
 * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE
 * or http://www.opensolaris.org/os/licensing.
 * See the License for the specific language governing permissions
 * and limitations under the License.
 *
 * When distributing Covered Code, include this CDDL HEADER in each
 * file and include the License file at usr/src/OPENSOLARIS.LICENSE.
 * If applicable, add the following below this CDDL HEADER, with the
 * fields enclosed by brackets "[]" replaced with your own identifying
 * information: Portions Copyright [yyyy] [name of copyright owner]
 *
 * CDDL HEADER END
 */
/*
 * Copyright 2011 Nexenta Systems, Inc.  All rights reserved.
 */
/*
 * Copyright 2006 Sun Microsystems, Inc.  All rights reserved.
 * Use is subject to license terms.
 */

#pragma weak exp10 = __exp10

/* INDENT OFF */
/*
 * exp10(x)
 * Code by K.C. Ng for SUN 4.0 libm.
 * Method :
 *  n = nint(x*(log10/log2));
 *  exp10(x) = 10**x = exp(x*ln(10)) = exp(n*ln2+(x*ln10-n*ln2))
 *       = 2**n*exp(ln10*(x-n*log2/log10)))
 *  If x is an integer < 23 then use repeat multiplication. For
 *  10**22 is the largest representable integer.
 */
/* INDENT ON */

#include "libm.h"

static const double C[] = {
    3.3219280948736234787,  /* log(10)/log(2) */
    2.3025850929940456840,  /* log(10) */
    3.0102999565860955045E-1,   /* log(2)/log(10) high */
    5.3716447674669983622E-12,  /* log(2)/log(10) low */
    0.0,
    0.5,
    1.0,
    10.0,
    1.0e300,
    1.0e-300,
};

#define lg10    C[0]
#define ln10    C[1]
#define logt2hi C[2]
#define logt2lo C[3]
#define zero    C[4]
#define half    C[5]
#define one C[6]
#define ten C[7]
#define huge    C[8]
#define tiny    C[9]

double
exp10(double x) {
    double  t, pt;
    int ix, hx, k;

    ix = ((int *)&x)[HIWORD];
    hx = ix & ~0x80000000;

    if (hx >= 0x4074a000) { /* |x| >= 330 or x is nan */
        if (hx >= 0x7ff00000) { /* x is inf or nan */
            if (ix == 0xfff00000 && ((int *)&x)[LOWORD] == 0)
                return (zero);
            return (x * x);
        }
        t = (ix < 0)? tiny : huge;
        return (t * t);
    }

    if (hx < 0x3c000000)
        return (one + x);

    k = (int)x;
    if (0 <= k && k < 23 && (double)k == x) {
        /* x is a small positive integer */
        t = one;
        pt = ten;
        if (k & 1)
            t = ten;
        k >>= 1;
        while (k) {
            pt *= pt;
            if (k & 1)
                t *= pt;
            k >>= 1;
        }
        return (t);
    }
    t = x * lg10;
    k = (int)((ix < 0)? t - half : t + half);
    return (scalbn(exp(ln10 * ((x - k * logt2hi) - k * logt2lo)), k));
}