test_lst.tex revision b5852f3dae4830d39b5127bfd0b732738809fbc5
\documentclass{article}
\usepackage{lstcasl}
\begin{document}
\begin{lstlisting}
library Datatypes
spec Nat =
free type Nat ::= 0 | suc(Nat)
ops __ + __ : Nat * Nat -> Nat;
forall m,n,k : Nat
. 0 + m = m %(add_0_Nat)%
. suc(n) + m = suc(n + m) %(add_suc_Nat)%
. m + 0 = m %(add_0_Nat_right)% %implied
. m+(n+k) = (m+n)+k %(add_assoc_Nat)% %implied
. m+suc(n) = suc(m+n) %(add_suc_Nat)% %implied
. m+n = n+m %(add_comm_Nat)% %implied
end
spec List[sort Elem] =
free type List[Elem] ::= [] | __::__(Elem; List[Elem])
end
spec Partial_Order =
sort Elem
pred __<=__ : Elem * Elem
forall x, y, z:Elem
. x <= x %(reflexive)%
. x <= y /\ y <= x => x=y %(antisymmetric)%
. x <= y /\ y <= z => x <= z %(transitive)%
%{ Note that there may exist x, y such that
neither x <= y nor y <= x. }%
end
spec Total_Order =
Partial_Order
then
forall x, y:Elem
. (x <= y) \/ (y <= x) %(total)%
end
spec ProblematicDefinitionOfSelectors [Total_Order] =
List[sort Elem]
then
ops head : List[Elem] -> Elem;
tail : List[Elem] -> List[Elem];
pred isOrdered : List[Elem]
forall x:Elem; l:List[Elem]
. head(x::l) = x
. tail(x::l) = l
. isOrdered([])
. isOrdered(x::[])
. isOrdered(l) <=> (head(l)<=head(tail(l)) /\ isOrdered(tail(l)))
then %implies
. false
end
spec Char =
free type Char ::= A | B
end
spec String =
List[Char fit Elem |-> Char] with List[Char] |-> String
end
spec StringList =
List[String fit Elem |-> String]
end
spec UnboundedBranchingTree [sort Elem] =
free types
Tree ::= Leaf(Elem) | Branch(Forest);
Forest ::= Nil | Cons(Tree;Forest)
end
\end{lstlisting}
\end{document}
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