Searched defs:minlen (Results 1 - 7 of 7) sorted by relevance
/osnet-11/usr/src/lib/gss_mechs/mech_krb5/krb5/krb/ |
H A D | addr_order.c | 46 const int minlen = min(addr1->length, addr2->length); local 54 for (i = 0; i < minlen; i++) {
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/osnet-11/usr/src/lib/libwanbootutil/common/ |
H A D | key_util.c | 118 uint_t len, uint_t minlen, uint_t maxlen, 124 attr->ka_minlen = minlen; 117 wbku_keyattr_init(wbku_key_attr_t *attr, wbku_key_type_t type, uint_t atype, uint_t len, uint_t minlen, uint_t maxlen, char *str, char *oid, boolean_t (*keycheck)(const uint8_t *)) argument
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/osnet-11/usr/src/cmd/perl/5.8.4/distrib/ |
H A D | regexp.h | 43 I32 minlen; /* mininum possible length of $& */ member in struct:regexp
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H A D | regexec.c | 364 lengths of all the strings are no more than minlen, thus they 366 (Or minlen should take into account lookahead.) */ 438 if (prog->minlen > strend - strpos) { 507 end_shift = prog->minlen - start_shift - 523 end_shift = prog->minlen - start_shift - 613 last2 = last1 = HOP3c(strend, -prog->minlen, strbeg); 671 HOP3c(strend, -prog->minlen + prog->float_min_offset, strbeg); 738 while (t < strend - prog->minlen) { 836 /* minlen == 0 is possible if regstclass is \b or \B, 838 Since minlen i 1617 I32 minlen; /* must match at least this many chars */ local [all...] |
H A D | regcomp.c | 677 /* deltap: Write maxlen-minlen here. */ 1743 I32 minlen = 0; local 1968 minlen = 0; 1983 minlen = study_chunk(pRExC_state, &first, &fake, scan + RExC_size, /* Up to end */ 2099 /* Several toplevels. Best we can is to set minlen. */ 2109 minlen = study_chunk(pRExC_state, &scan, &fake, scan + RExC_size, &data, SCF_DO_STCLASS_AND|SCF_WHILEM_VISITED_POS); 2132 r->minlen = minlen; 4684 PerlIO_printf(Perl_debug_log, "minlen %ld ", (long) r->minlen); [all...] |
/osnet-11/usr/src/lib/libkmf/include/ |
H A D | kmfapiP.h | 156 uint32_t minlen; member in struct:__anon1832
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/osnet-11/usr/src/grub/grub2/grub-core/fs/ |
H A D | hfs.c | 622 int minlen = (k1->strlen < k2->strlen) ? k1->strlen : k2->strlen; 628 for (i = 0; i < minlen; i++) 621 int minlen = (k1->strlen < k2->strlen) ? k1->strlen : k2->strlen; local
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