Lines Matching refs:next
54 struct _EntryRec *next;
84 Entry next;
89 next = (dict->entries)[links];
90 while (next != NIL)
92 prev = next;
93 next = next->next;
113 for (e = (d->entries)[x]; e != NIL; e = e->next) {
123 for (e = (d->entries)[x]; e != NIL; e = e->next) {
151 e->next = (dict->entries)[x]; (dict->entries)[x] = e;
167 if (prev == NIL) (dict->entries)[x] = e->next; else prev->next = e->next;
182 e->next = (atoms->entries)[x]; (atoms->entries)[x] = e;