Lines Matching defs:longword1
82 to testing whether *any of the four* bytes in longword1 or
85 Let's consider longword1. We compute tmp =
86 ((longword1 - repeated_one) & ~longword1) & (repeated_one << 7).
89 2. & ~longword1.
92 - If a byte of longword1 is zero, step 1 and 2 transform it into 0xff,
95 - If a byte of longword1 is nonzero, let its lowest 1 bit be at
100 So, if longword1 has only non-zero bytes, tmp is zero.
101 Whereas if longword1 has a zero byte, call j the position of the least
107 The test whether any byte in longword1 or longword2 is zero is equivalent
119 longword longword1 = *longword_ptr ^ repeated_c;
122 if (((((longword1 - repeated_one) & ~longword1)