Lines Matching defs:expl
31 * expl(x)39 * 2. expl(x) = 2^k * (2^(j/32) + 2^(j/32)*expm1(r))49 * expl(INF) is INF, expl(NaN) is NaN;50 * expl(-INF)= 0;51 * for finite argument, only expl(0)=1 is exact.60 * then expl(x) overflow;62 * then expl(x) underflow70 #pragma weak __expl = expl95 expl(long double x) {